We study some properties of the Prüfer p-group Zp∞ for a prime number p. The Prüfer p-group may be identified with the subgroup of the circle group, consisting of all pn-th roots of unity as n ranges over all non-negative integers:
Zp∞=∞⋃k=0Zpk where Zpk={e2iπmpk | 0≤m≤pk−1}
Zp∞ is a group
First, let’s notice that for 0≤m≤n integers we have Zpm⊆Zpn as pm|pn. Also for m≥0 Zpm is a subgroup of the circle group. We also notice that all elements of Zp∞ have finite orders which are powers of p.
Now for z1,z2 elements of Zp∞, there exist k1,k2≥0 with z1∈Zpk1 and z2∈Zpk2. We can suppose without loss of generality that k1≤k2. Hence z1,z2 ∈Zpk2 and z1z−12∈Zpk2⊆Zp∞ which proves that Zp∞ is a subgroup of the unit circle.
All subgroups of Zp∞ are finite
Let H be a proper subgroup of Zp∞. We prove that H is equal to one of the Zpn for n≥0. If the set of the orders of elements of H is infinite, then for all element z∈Zp∞ of order pk, there would exist an element z′∈H of order pk′>pk. Hence H would contain Zp′ and z∈H. Finally Zp∞ would be included in H in contradiction with the hypothesis that H is a proper subgroup.
Therefore the set of the orders of the elements of H is finite. If h∈H is an element with maximum order pn, we have H=Zpn.
In conclusion:
- Zp∞ is an infinite group whose proper subgroups are all finite.
- It is a non-cyclic group whose all proper subgroups are cyclic.