the-prufer-group-image

An infinite group whose proper subgroups are all finite

We study some properties of the Prüfer p-group Zp for a prime number p. The Prüfer p-group may be identified with the subgroup of the circle group, consisting of all pn-th roots of unity as n ranges over all non-negative integers:
Zp=k=0Zpk where Zpk={e2iπmpk | 0mpk1}

Zp is a group

First, let’s notice that for 0mn integers we have ZpmZpn as pm|pn. Also for m0 Zpm is a subgroup of the circle group. We also notice that all elements of Zp have finite orders which are powers of p.

Now for z1,z2 elements of Zp, there exist k1,k20 with z1Zpk1 and z2Zpk2. We can suppose without loss of generality that k1k2. Hence z1,z2 Zpk2 and z1z12Zpk2Zp which proves that Zp is a subgroup of the unit circle.

All subgroups of Zp are finite

Let H be a proper subgroup of Zp. We prove that H is equal to one of the Zpn for n0. If the set of the orders of elements of H is infinite, then for all element zZp of order pk, there would exist an element zH of order pk>pk. Hence H would contain Zp and zH. Finally Zp would be included in H in contradiction with the hypothesis that H is a proper subgroup.

Therefore the set of the orders of the elements of H is finite. If hH is an element with maximum order pn, we have H=Zpn.

In conclusion:

  • Zp is an infinite group whose proper subgroups are all finite.
  • It is a non-cyclic group whose all proper subgroups are cyclic.

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